![]() I created a small snippet to illustrate my problem. How to I overcome it by skipping those entry without dot(.). Using String.substring() The easiest way is to use the built-in substring() method of the String class. String substring () The substring () method has two variants and returns a new string that is a substring of this string. I will get an error Exception in thread "main" : String index out of range: -1 Use a better overload like String.split (String regex, int limit). ![]() String wantedPart lineOfText.substring (lineOfText.indexOf (',') + 1) Since indexOf returns the index of the, itself, you need to add one to get everything past it. ![]() I want to input the data into a Hashmap and do some datamapping. Find the index (position) of the first, and substring using that index. But I don't know what the last number is going to be since the html is always changing.I have a text file data.txt. Html.substring(html.indexOf("test"), 22) The arguments say that the substring starts at the 9th character of the string and that its length is 10 characters. indexOf (char): String substrmysourcestring.substring (mysourcestring. SELECT SUBSTRING('This is the first substring example', 9, 10) AS substringextraction This means: I want to find a substring from the text ‘This is the first substring example’. Working code would be the following String html = "This is a test string for example" If you want to get substring from specific character till end you can use : String substrmysourcestring.substring (mysourcestring.indexOf ('characterValue')) If you want to get substring from after a specific character, add that number to. 2 - take a new substring from the last index of the substring to the last index of the main string and check if it contains the search string 3 - repeat the steps in a loop. This matches at a certain position in the string, namely at a position right after the text sentence without making that text itself part of the match. Like its manual says, it works like this: A null input String returns null. That's more convenient than the one provided by Java out of the box if you don't need regular expressions. String str '123dance456' String substr 'dance' String parts str.split(substr) String before parts0 String after parts1 It is noteworthy that the second answer not work if we have more than one occurrence of the substring. However if I use this code I get a indexOutOfBounds exception because 6 is before test. 1 - check if the last index of substring is not the end of the main string. The easiest way is to use StringUtilssplit(, char). ![]() This is an example of how I would like the code to work, it would make a substring starting at test and stop after 7 characters returning "test string". String html = "This is a test string for example" String str '123dance456' String substr 'dance' String parts str. substring method in Java works is you have to give it a start location and a end location but the end location needs to be a location on the original string after the start. So I'm parsing html and I'm trying to create a substring starting at a certain location and stop 941 characters after that. ![]()
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